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BADXOR

BADXOR - Bad XOR


#include <iostream>
#include <cstring>

#define REP(i, n) for(int i = 0; i < n; i++)
#define REP1(i, n) for(int i = 1; i <= n; i++)

using namespace std;

typedef long long int ll;

const int maxLimit = 100000007;

ll dp[1005][1024];
//dp[i][j] = number of ways of making value j with first i elements

int main()
{
    int t, a, b;
    int arr1[1001];
    bool arr2[1025];
    cin >> t;

    REP1(k, t)
    {
        memset(dp, 0, sizeof(dp));
        memset(arr2, false, sizeof(arr2));

        cin >> a >> b;

        REP(i, a)
        {
            cin >> arr1[i];
        }

        REP(i, b)
        {
            int temp;
            cin >> temp;
            arr2[temp] = true;
        }

        dp[0][0] = 1;

        REP1(i, a)
        {
            REP(j, 1024)
            {
                dp[i][j] = dp[i - 1][j] + dp[i - 1][j ^ arr1[i - 1]];

                if(dp[i][j] >= maxLimit)
                    dp[i][j] -= maxLimit;
            }
        }


        ll total = 0; // number of subset

        REP(i, 1024)
        {
            if(!arr2[i])
            {
                total += dp[a][i];
                if(total >= maxLimit)
                total -= maxLimit;
            }

        }

        cout << "Case " << k << ": " << total << endl;

    }
    return 0;
}

Comments

  1. Unknown21 December 2018 at 23:34

    can somesone post the solution of BADXOR using topdown approach

    ReplyDelete

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